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'task command' how to work with local variables

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3 comments

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    Sushma Chaluvadi

    I noticed this pattern while working on converting a bash script that I was using locally into a WDL task. I have very much simplified the task but what I noticed is that variables that are defined in the input block of the task are referenced with the `~{myVar}` and then any variables that are created within the task - so, I guess the local variables for the task's VM - have to be referenced as `"$myVar"`. So, in my example below, I defined `~{id_details}` was defined in the input block and then `"$job_id"` was a local variable. Not entirely sure if that helps answer your question but it was what ended up working for me as I transferred by bash code into WDL format.

    task demo_variables {
    input {
    File id_details
    String docker
    }
    command <<<
    awk '{print $1}' OFS="\t" ~{id_details} > id_list.txt

    while IFS="\t" read -r job_id
    do
    bq wait "$job_id"
    echo "$job_id"
    done < job_id_list.txt >> final_details.txt
    >>>

    runtime {
    docker: docker
    }
    output {
    File final_details = "final_details.txt"
    }
    }
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    Andrew Davidson

    Hi Sushma

    thanks for the tip. I think there is a bug in Cromwell. if you comment out a line in your bash task, Cromwell will still try to expand it. this will cause an error if the variable is not defined

     

    Andy

     

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    Samantha (she/her)

    Hi Andrew Davidson,

    Sorry for the late response. Can you please paste your full test WDL? I was not able to replicate the error when I tested with each of the following:

    # echo ${myVar} 
    # echo \$myVar
    # how to local variables work?
    # you can not use \$\{var\} you must use dollar var
    count=`ls . | wc -l`
    echo "the number of files in . is $count"

     

    Best,

    Samantha

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